Source code for surrogate.sorting.sorNDHelperB
# Copyright 2016 Quan Pan
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.
#
# Author: Quan Pan <quanpan302@hotmail.com>
# License: Apache License, Version 2.0
# Create: 2016-12-02
from operator import itemgetter
from .utils import isDominated, sweepB, splitB
[docs]def sorNDHelperB(best, worst, obj, front):
"""Assign front numbers to the solutions in H according to the solutions
in L. The solutions in L are assumed to have correct front numbers and the
solutions in H are not compared with each other, as this is supposed to
happen after sorNDHelperB is called."""
key = itemgetter(obj)
if len(worst) == 0 or len(best) == 0:
# One of the lists is empty: nothing to do
return
elif len(best) == 1 or len(worst) == 1:
# One of the lists has one individual: compare directly
for hi in worst:
for li in best:
if isDominated(hi[:obj + 1], li[:obj + 1]) or hi[:obj + 1] == li[:obj + 1]:
front[hi] = max(front[hi], front[li] + 1)
elif obj == 1:
sweepB(best, worst, front)
elif key(min(best, key=key)) >= key(max(worst, key=key)):
# All individuals from L dominate H for objective M:
# Also supports the case where every individuals in L and H
# has the same value for the current objective
# Skip to objective M-1
sorNDHelperB(best, worst, obj - 1, front)
elif key(max(best, key=key)) >= key(min(worst, key=key)):
best1, best2, worst1, worst2 = splitB(best, worst, obj)
sorNDHelperB(best1, worst1, obj, front)
sorNDHelperB(best1, worst2, obj - 1, front)
sorNDHelperB(best2, worst2, obj, front)